Question:

Let H be a subgroup of a group G, where $O(H) = m$ and $O(G) = n$. Then, for any $a \in G$, $O(aH) = $

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All cosets of a subgroup $H$ have the same size as $H$ itself. They "partition" the group into equal-sized pieces.
  • $m$
  • $n$
  • $mn$
  • $m+n$
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The Correct Option is A

Solution and Explanation

Step 1: Concept
This relates to the properties of cosets in group theory.

Step 2: Meaning

$aH$ denotes a left coset of $H$ in $G$, which is the set $\{ah : h \in H\}$.

Step 3: Analysis

There is a one-to-one correspondence between $H$ and any of its cosets $aH$ defined by the map $f(h) = ah$.

Step 4: Conclusion

Because the map is a bijection, the number of elements (order) in the coset $aH$ is exactly the same as the order of the subgroup $H$, which is $m$. Final Answer: (A)
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