Question:

In the group $(R-\{-1\}, *)$ where $*$ is defined by $a*b = a+b+ab, \forall a,b \in R-\{-1\}$, inverse of the element 2 is}

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Always find the identity ($e$) first; the inverse is the value that "undoes" the element to get back to $e$.
  • $\frac{1}{2}$
  • $-\frac{2}{3}$
  • $-\frac{3}{2}$
  • $-\frac{1}{2}$
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The Correct Option is B

Solution and Explanation

Step 1: Concept
To find the inverse, first find the identity element $e$ such that $a*e = a$. Then find $b$ such that $a*b = e$.

Step 2: Meaning

$a+e+ae = a \Rightarrow e(1+a) = 0 \Rightarrow e = 0$. The identity element is 0.

Step 3: Analysis

To find the inverse of 2, set $2*b = 0 \Rightarrow 2+b+2b = 0$.

Step 4: Conclusion

$2 + 3b = 0 \Rightarrow 3b = -2 \Rightarrow b = -2/3$. The inverse of 2 is $-2/3$. Final Answer: (B)
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