Step 1: Evaluate \(f(0)\).
\[
f(0)=[\tan^2 0]=[0]=0
\] Step 2: Check behaviour near \(x=0\).
For small \(x\):
\[
\tan x \approx x \Rightarrow \tan^2 x \approx x^2
\]
So for \(x\) close to 0:
\[
0 \le \tan^2 x<1
\]
Hence:
\[
[\tan^2 x]=0
\] Step 3: Compute limit.
\[
\lim_{x\to 0} f(x)=\lim_{x\to 0} [\tan^2 x]=0
\] Step 4: Compare with \(f(0)\).
\[
\lim_{x\to 0} f(x)=0=f(0)
\]
So \(f(x)\) is continuous at \(x=0\). Final Answer:
\[
\boxed{\text{(B) } f(x)\text{ is continuous at }x=0}
\]