Step 1: Simplify
\(\frac{x}{x^{5/2}+4x^{3/2}}=\frac{x}{x^{3/2}(x+4)}=\frac{1}{\sqrt{x}(x+4)}\).
Step 2: Substitute
Let \(t=\sqrt{x}\), so \(dx=2t\,dt\).
Step 3: Integrate
\(\int \frac{2t\,dt}{t(t^{2}+4)}=2\int \frac{dt}{t^{2}+4}=2\cdot \frac{1}{2}\tan ^{-1}\frac{t}{2}\).
Step 4: Substitute back
The result is \(\tan ^{-1}\left(\frac{\sqrt{x}}{2}\right)+c\).
Final Answer:
The integral is \(\tan ^{-1}\left(\frac{\sqrt{x}}{2}\right)+c\).
\[ \boxed{\text{(D) }\tan ^{-1}\left(\dfrac{\sqrt{x}}{2}\right)+c} \]