Question:
In Young’s double slit experiment, when wavelength used is 600 Å and the screen is 40 cm from the slits, then the fringes are 0.012 cm apart. What is the distance between the slits?
In Young’s double slit experiment, when wavelength used is 600 Å and the screen is 40 cm from the slits, then the fringes are 0.012 cm apart. What is the distance between the slits?
Show Hint
Fringe width $β = \fracλ Dd$.
Updated On: Apr 16, 2026
- 0.024 cm
- 2.4 cm
- 0.24 cm
- 0.2 cm
Show Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Fringe width $β = \fracλ Dd$.
Step 2: $λ = 600 Å = 6 × 10^-5 cm$, $D = 40 cm$, $β = 0.012 cm$.
Step 3: $d = \fracλ Dβ = \frac6 × 10^-5 × 400.012 = 0.2 cm$.
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