Question:
In which of the molecules lone pair, bond pair of electrons ratio is \(2:3\)?
In which of the molecules lone pair, bond pair of electrons ratio is \(2:3\)?
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In \(N_2\), there is a triple bond, so bond pairs are \(3\), and each nitrogen has one lone pair, so total lone pairs are \(2\).
Updated On: May 7, 2026
- \(Cl_2\)
- \(O_2\)
- \(HCl\)
- \(N_2\)
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The Correct Option is D
Solution and Explanation
We need to find the molecule in which the ratio of lone pair of electrons to bond pair of electrons is:
\[
2:3.
\]
Consider nitrogen molecule:
\[
N_2.
\]
Nitrogen has atomic number \(7\), so its valence electronic configuration is:
\[
2s^2 2p^3.
\]
Each nitrogen atom has \(5\) valence electrons.
In \(N_2\), the two nitrogen atoms form a triple bond:
\[
N\equiv N.
\]
A triple bond contains:
\[
3
\]
bond pairs of electrons.
Each nitrogen atom still has one lone pair.
So total lone pairs in \(N_2\) are:
\[
2.
\]
Total bond pairs are:
\[
3.
\]
Therefore, the ratio is:
\[
\text{Lone pairs}:\text{Bond pairs}=2:3.
\]
Hence, the required molecule is:
\[
N_2.
\]
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