Question:
In which of the following, the number of bonding electrons and non-bonding electrons are in \(3:2\) ratio?
In which of the following, the number of bonding electrons and non-bonding electrons are in \(3:2\) ratio?
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In \(N_2\), the triple bond gives \(6\) bonding electrons and two lone pairs give \(4\) non-bonding electrons.
Updated On: May 7, 2026
- \(N_2\)
- \(O_2\)
- \(HCl\)
- \(F_2\)
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The Correct Option is A
Solution and Explanation
Concept:
Bonding electrons are those electrons that participate in bond formation, while non-bonding electrons remain as lone pairs.
Step 1: In nitrogen molecule: \[ N_2 \] The structure is: \[ :N\equiv N: \]
Step 2: A triple bond contains: \[ 3 \text{ bond pairs} \] So bonding electrons: \[ 3\times 2=6 \]
Step 3: Each nitrogen atom has one lone pair. So total non-bonding electrons: \[ 2+2=4 \]
Step 4: Ratio of bonding electrons to non-bonding electrons: \[ 6:4=3:2 \] Therefore, \[ \boxed{N_2} \]
Step 1: In nitrogen molecule: \[ N_2 \] The structure is: \[ :N\equiv N: \]
Step 2: A triple bond contains: \[ 3 \text{ bond pairs} \] So bonding electrons: \[ 3\times 2=6 \]
Step 3: Each nitrogen atom has one lone pair. So total non-bonding electrons: \[ 2+2=4 \]
Step 4: Ratio of bonding electrons to non-bonding electrons: \[ 6:4=3:2 \] Therefore, \[ \boxed{N_2} \]
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