Question:
Consider the elements with atomic numbers \(Z=8,9,11,19\) and \(20\). The number of ionic compounds possible with the elements having these atomic numbers is
Consider the elements with atomic numbers \(Z=8,9,11,19\) and \(20\). The number of ionic compounds possible with the elements having these atomic numbers is
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Ionic compounds are formed between metals and non-metals. First identify the elements from atomic numbers, then count metal-nonmetal combinations.
Updated On: May 7, 2026
- \(6\)
- \(5\)
- \(10\)
- \(8\)
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The Correct Option is A
Solution and Explanation
First identify the elements.
\[
Z=8 \Rightarrow O
\]
\[
Z=9 \Rightarrow F
\]
\[
Z=11 \Rightarrow Na
\]
\[
Z=19 \Rightarrow K
\]
\[
Z=20 \Rightarrow Ca
\]
Oxygen and fluorine are non-metals.
Sodium, potassium, and calcium are metals.
Ionic compounds are generally formed between metals and non-metals.
Now possible combinations are:
With oxygen:
\[
Na_2O,\quad K_2O,\quad CaO.
\]
With fluorine:
\[
NaF,\quad KF,\quad CaF_2.
\]
So total ionic compounds possible are:
\[
3+3=6.
\]
Therefore, the number of ionic compounds possible is:
\[
6.
\]
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