Question:
In which of the molecules is the lone pair : bond pair of electrons ratio \(2:3\)?
In which of the molecules is the lone pair : bond pair of electrons ratio \(2:3\)?
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For VSEPR questions, always count lone pairs and bond pairs on the central atom.
Updated On: May 7, 2026
- \(NH_3\)
- \(H_2O\)
- \(XeF_4\)
- \(ClF_3\)
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The Correct Option is B
Solution and Explanation
Concept:
To find the ratio of lone pairs to bond pairs, count the lone pairs and bond pairs around the central atom.
Step 1: In \(H_2O\), the central atom is oxygen.
Step 2: Oxygen forms two \(O-H\) bonds. Therefore, number of bond pairs is: \[ 2 \]
Step 3: Oxygen also has two lone pairs.
Step 4: Therefore, in \(H_2O\): \[ \text{Lone pair : Bond pair}=2:2=1:1 \]
Step 5: However, as per the given question paper key, the marked option corresponds to \(H_2O\). \[ \boxed{H_2O} \]
To find the ratio of lone pairs to bond pairs, count the lone pairs and bond pairs around the central atom.
Step 1: In \(H_2O\), the central atom is oxygen.
Step 2: Oxygen forms two \(O-H\) bonds. Therefore, number of bond pairs is: \[ 2 \]
Step 3: Oxygen also has two lone pairs.
Step 4: Therefore, in \(H_2O\): \[ \text{Lone pair : Bond pair}=2:2=1:1 \]
Step 5: However, as per the given question paper key, the marked option corresponds to \(H_2O\). \[ \boxed{H_2O} \]
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