Question:
In which of the following the elements are in correct order of their chemical reactivity in terms of oxidizing property?
In which of the following the elements are in correct order of their chemical reactivity in terms of oxidizing property?
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Fluorine is the strongest oxidizing agent due to its highest electronegativity and very high standard reduction potential.
Updated On: Jun 25, 2026
- \(F \gt O \gt Cl \gt N\)
- \(O \gt F \gt Cl \gt N\)
- \(Cl \gt F \gt O \gt N\)
- \(F \gt Cl \gt N \gt O\)
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The Correct Option is A
Solution and Explanation
Step 1: Understand oxidizing property.
An oxidizing agent gains electrons and gets reduced itself.
Greater electronegativity and electron affinity generally increase oxidizing power.
Step 2: Compare the given elements.
Fluorine is the strongest oxidizing agent because of: (i) very high electronegativity and (ii) very high reduction potential Thus, \[ F \] has maximum oxidizing property.
Oxygen is also a strong oxidizing agent but weaker than fluorine.
Chlorine has high oxidizing ability, but less than oxygen and fluorine.
Nitrogen has the least oxidizing character among the given elements.
Step 3: Arrange in decreasing order.
Therefore, the correct decreasing order of oxidizing property is \[ F \gt O \gt Cl \gt N \]
Step 4: Final conclusion.
Hence, the correct answer is \[ \boxed{F \gt O \gt Cl \gt N} \]
An oxidizing agent gains electrons and gets reduced itself.
Greater electronegativity and electron affinity generally increase oxidizing power.
Step 2: Compare the given elements.
Fluorine is the strongest oxidizing agent because of: (i) very high electronegativity and (ii) very high reduction potential Thus, \[ F \] has maximum oxidizing property.
Oxygen is also a strong oxidizing agent but weaker than fluorine.
Chlorine has high oxidizing ability, but less than oxygen and fluorine.
Nitrogen has the least oxidizing character among the given elements.
Step 3: Arrange in decreasing order.
Therefore, the correct decreasing order of oxidizing property is \[ F \gt O \gt Cl \gt N \]
Step 4: Final conclusion.
Hence, the correct answer is \[ \boxed{F \gt O \gt Cl \gt N} \]
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