Step 1: Understanding the Concept:
For an ideal gas, internal energy \(U\) depends only on temperature. So \(U\) stays constant only when the temperature stays constant.
Step 2: Check each process:
Isobaric process: pressure is constant but the volume and temperature change, so \(U\) changes. This is wrong.
Isochoric process: volume is constant, so no work is done, but heat added raises the temperature and \(\Delta U = q_V \neq 0\). This is wrong.
Isothermal process: temperature is constant, so \(\Delta T = 0\) and \(\Delta U = 0\). This is correct, and the heat absorbed equals the work done by the gas.
Adiabatic process: \(q = 0\), but \(\Delta U = w \neq 0\), so the temperature changes. This is wrong.
Final Answer:
Only the isothermal process keeps the internal energy constant, which is option (C).
\[ \boxed{\text{Isothermal process}} \]