Question:
In which of the following molecules $S$ atom does not assume $sp ^{3}$ hybridsation?
In which of the following molecules $S$ atom does not assume $sp ^{3}$ hybridsation?
Updated On: Apr 14, 2026
- $SO_4^{2-}$
- $SF_4$
- $SF_2$
- $SF_8$
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The Correct Option is B
Solution and Explanation
In $SO _{4}^{2-} \Rightarrow bp =4, lp =0 $
$ \therefore$ hybridisation $sp ^{3}$
In SF $_{4} \Rightarrow bp =4, lp =1 $
$ \therefore$ hybridisation $sp ^{3} d$
In $SF _{2} \Rightarrow bp =2, lp =2 $
$\therefore$ hybridisation $sp ^{3}$
In $S _{8} \Rightarrow bp =2, lp =2 $
$ \therefore$ hybridisation $sp ^{3}$
Thus, only $SF _{4}$ does not have $sp ^{3}$ hybridisation.
$ \therefore$ hybridisation $sp ^{3}$
In SF $_{4} \Rightarrow bp =4, lp =1 $
$ \therefore$ hybridisation $sp ^{3} d$
In $SF _{2} \Rightarrow bp =2, lp =2 $
$\therefore$ hybridisation $sp ^{3}$
In $S _{8} \Rightarrow bp =2, lp =2 $
$ \therefore$ hybridisation $sp ^{3}$
Thus, only $SF _{4}$ does not have $sp ^{3}$ hybridisation.
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