Question:

In which of the following ions are correctly arranged with respect to their mobilities in aqueous solution?

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Greater hydration = lower mobility. Smaller ions are more strongly hydrated.
Updated On: Jun 19, 2026
  • \(K^+ > Na^+ > Cs^+ > Li^+\)
  • \(Li^+ > K^+ > Na^+ > Cs^+\)
  • \(Cs^+ > K^+ > Na^+ > Li^+\)
  • \(Na^+ > K^+ > Cs^+ > Li^+\)
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The Correct Option is C

Solution and Explanation

Step 1: Understanding ionic mobility.
Ionic mobility in aqueous solution depends mainly on ionic size and hydration. Smaller ions have higher charge density and get heavily hydrated, which reduces their mobility.

Step 2: Hydration effect.

Among alkali metal ions, \(Li^+\) is the smallest and gets most strongly hydrated, hence shows lowest mobility. \(Cs^+\) is largest and least hydrated, hence highest mobility.

Step 3: Trend analysis.

Therefore, mobility increases as hydration decreases: \[ Cs^+ > K^+ > Na^+ > Li^+ \]

Step 4: Final justification.

The trend is governed by effective hydrated radius rather than bare ionic radius. Larger ions move more freely in solution.

Step 5: Final conclusion.

Thus, correct order of mobility is \(Cs^+ > K^+ > Na^+ > Li^+\).
Final Answer: \[ \boxed{Cs^+ > K^+ > Na^+ > Li^+} \]
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