In two circuit shown above the value of current I1 (in amperes) is equal to \(-\frac{y}{5}A\) . Value of y is equal to
Correct Answer: 11
Solution and Explanation
We use Kirchhoff's current and voltage laws to solve for the unknown currents.
Step 1: Kirchhoff's Current Law (KCL):
The first equation is given by:
\[ I_1 + I_3 - I_2 = -2 ag{1} \]
Step 2: Kirchhoff's Voltage Law (KVL):
The second equation is:
\[ I_3 + 2I_2 = 5 ag{2} \]
Step 3: Substituting into KVL:
The third equation is:
\[ 2I_2 - (I_3 - I_2) - (I_1 + I_3 - I_2) = 5 ag{3} \]
Solving the Equations:
From equation (3):
\[ I_1 = -\frac{11}{5} \, \text{A} \]
Therefore:
\[ y = 11 \]
Final Answer:
\(y = 11\)
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