We use Kirchhoff's current and voltage laws to solve for the unknown currents.
The first equation is given by:
\[ I_1 + I_3 - I_2 = -2 ag{1} \]
The second equation is:
\[ I_3 + 2I_2 = 5 ag{2} \]
The third equation is:
\[ 2I_2 - (I_3 - I_2) - (I_1 + I_3 - I_2) = 5 ag{3} \]
From equation (3):
\[ I_1 = -\frac{11}{5} \, \text{A} \]
Therefore:
\[ y = 11 \]
\(y = 11\)




