Question:

In \(\triangle ABC\), \(O\) is the circumcenter and \(G\) is the centroid, then \[ OG^2= \] is:

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For a triangle, the distance between circumcenter \(O\) and centroid \(G\) is given by \[ OG^2=R^2-\frac{1}{9}(a^2+b^2+c^2) \] This is a standard result from triangle geometry.
Updated On: Jun 24, 2026
  • \(R^2-\dfrac{1}{3}(a^2+b^2+c^2)\)
  • \(R^2-\dfrac{1}{6}(a^2+b^2+c^2)\)
  • \(R^2-\dfrac{1}{9}(a^2+b^2+c^2)\)
  • \(R-\dfrac{1}{9}(a^2+b^2+c^2)\)
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Recall the standard formula.
In a triangle, if \(O\) is the circumcenter and \(G\) is the centroid, then the distance between them is given by \[ OG^2=R^2-\frac{1}{9}(a^2+b^2+c^2) \] Here, \(R\) is the circumradius and \(a,b,c\) are the side lengths of the triangle.

Step 2: Compare with the given options.
The formula \[ OG^2=R^2-\frac{1}{9}(a^2+b^2+c^2) \] matches option (3).

Step 3: Final conclusion.
Therefore, \[ \boxed{R^2-\frac{1}{9}(a^2+b^2+c^2)} \]
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