Question:

In a triangle $ABC$, if $a = 13$, $b = 14$, $c = 15$, then the area of the triangle is:

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A triangle with sides $13, 14, 15$ is a standard classic triangle in geometry problems; its area is always $84$, and its semi-perimeter is $21$. Remembering this saves valuable time.
Updated On: Jun 3, 2026
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The Correct Option is A

Solution and Explanation

Step 1: Concept
The area of a triangle with known side lengths $a$, $b$, and $c$ can be calculated using Heron's Formula: $\Delta = \sqrt{s(s-a)(s-b)(s-c)}$, where $s = \frac{a+b+c}{2}$ is the semi-perimeter.

Step 2: Meaning
Here, the side lengths are $13$, $14$, and $15$.

Step 3: Analysis
First, calculate the semi-perimeter $s$: \[ s = \frac{13 + 14 + 15}{2} = \frac{42}{2} = 21 \] Now, substitute $s$ and the sides into Heron's Formula: \[ \Delta = \sqrt{21(21-13)(21-14)(21-15)} = \sqrt{21 \times 8 \times 7 \times 6} \] Simplify the terms inside the square root: \[ \Delta = \sqrt{(3 \times 7) \times (2^3) \times 7 \times (2 \times 3)} = \sqrt{7^2 \times 3^2 \times 2^4} \] \[ \Delta = 7 \times 3 \times 2^2 = 21 \times 4 = 84 \]

Step 4: Conclusion
The area of the triangle $ABC$ is exactly $84$ square units.

Final Answer: (A)
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