Step 1: Concept
The area of a triangle with known side lengths $a$, $b$, and $c$ can be calculated using Heron's Formula: $\Delta = \sqrt{s(s-a)(s-b)(s-c)}$, where $s = \frac{a+b+c}{2}$ is the semi-perimeter.
Step 2: Meaning
Here, the side lengths are $13$, $14$, and $15$.
Step 3: Analysis
First, calculate the semi-perimeter $s$:
\[ s = \frac{13 + 14 + 15}{2} = \frac{42}{2} = 21 \]
Now, substitute $s$ and the sides into Heron's Formula:
\[ \Delta = \sqrt{21(21-13)(21-14)(21-15)} = \sqrt{21 \times 8 \times 7 \times 6} \]
Simplify the terms inside the square root:
\[ \Delta = \sqrt{(3 \times 7) \times (2^3) \times 7 \times (2 \times 3)} = \sqrt{7^2 \times 3^2 \times 2^4} \]
\[ \Delta = 7 \times 3 \times 2^2 = 21 \times 4 = 84 \]
Step 4: Conclusion
The area of the triangle $ABC$ is exactly $84$ square units.
Final Answer: (A)