Step 1: Understanding the Question:
We are given an alphanumeric-symbol sequence and must find which of the five given combinations follow the same structural positioning pattern from the sequence.
Step 2: Key Formula or Approach:
Let us write down the indexed positions of each element in the sequence from left to right:
\[ \begin{array}{ccccccccccccccccc} 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 & 11 & 12 & 13 & 14 & 15 & 16 & 17 \text{S} & 7 & \text{@} & \text{P} & \text{B} & 6 & \text{\#} & \text{!} & 4 & \text{Q} & \text{\$} & \text{A} & \text{T} & \text{K} & \beta & 8 & \text{M} \end{array} \]
Step 3: Detailed Explanation:
Let us test the positioning pattern for each combination:
• Combination A: A K 4
Position of A = 12
Position of K = 14 ($\text{shift} = +2$ from A)
Position of 4 = 9 ($\text{shift} = -5$ from K)
Pattern followed: $(+2, -5)$.
• Combination B: Q A !
Position of Q = 10
Position of A = 12 ($\text{shift} = +2$ from Q)
Position of ! = 8 ($\text{shift} = -4$ from A)
Pattern followed: $(+2, -4)$.
• Combination C: $\beta$ M T
Position of $\beta$ = 15
Position of M = 17 ($\text{shift} = +2$ from $\beta$)
Position of T = 13 ($\text{shift} = -4$ from M)
Pattern followed: $(+2, -4)$.
• Combination D: # 4 P
Position of # = 7
Position of 4 = 9 ($\text{shift} = +2$ from #)
Position of P = 4 ($\text{shift} = -5$ from 4)
Pattern followed: $(+2, -5)$.
• Combination E: 6 ! @
Position of 6 = 6
Position of ! = 8 ($\text{shift} = +2$ from 6)
Position of @ = 3 ($\text{shift} = -5$ from !)
Pattern followed: $(+2, -5)$.
Comparing the results, combinations A, D, and E follow the exact same pattern of $(+2, -5)$ positions.
Step 4: Final Answer:
Combinations A, D, and E follow the pattern, which corresponds to option (B).