Step 1: Understanding the Question:
This is a direction sense and distance problem. We need to plot the movements of both husband and wife from their home (starting point) on a coordinate plane, and then find the distance and direction of the wife's office relative to the husband's office.
Step 2: Key Formula or Approach:
Let us set the starting point (home) at the origin $(0, 0)$.
• North represents positive Y-axis, South represents negative Y-axis.
• East represents positive X-axis, West represents negative X-axis.
• Distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
Step 3: Detailed Explanation:
Let us trace the paths:
• Husband's Path:
Starts at $(0, 0)$.
Drives 3 km South: reaches coordinates $(0, -3)$.
Turns to his right: Facing South, turning right means turning towards the West (negative X-direction).
Drives 2 km West: reaches final coordinates $(-2, -3)$.
So, Husband's Office ($H$) is at $(-2, -3)$.
• Wife's Path:
Starts at $(0, 0)$.
Drives 2 km East (positive X-direction): reaches coordinates $(2, 0)$.
So, Wife's Office ($W$) is at $(2, 0)$.
• Find distance and direction of $W$ with respect to $H$:
We need the vector from $H(-2, -3)$ to $W(2, 0)$: \[ \Delta x = x_W - x_H = 2 - (-2) = 4\text{ km} \] \[ \Delta y = y_W - y_H = 0 - (-3) = 3\text{ km} \] Using Pythagoras theorem: \[ d = \sqrt{(\Delta x)^2 + (\Delta y)^2} = \sqrt{4^2 + 3^2} = \sqrt{16 + 9} = \sqrt{25} = 5\text{ km} \] Since $\Delta x = +4$ (East) and $\Delta y = +3$ (North), the direction from the husband's office to the wife's office is North-East.
Step 4: Final Answer:
The wife's office is 5 km, North-east with respect to the husband's office. This corresponds to option (A).