In the process, O\(_2^+\) \(\rightarrow\) O\(_2^{2+}\) + e\(^-\), the electron lost is from
Show Hint
- bonding \(\pi\)-orbital
- antibonding \(\pi\)-orbital
- 2p\(_z\) orbital
- 2p\(_x\) orbital
The Correct Option is A
Solution and Explanation
Molecular orbital configuration of O\(_2^+\).
Step 2: Detailed Explanation:
O\(_2^+\) has configuration: ... (\(\pi\)2p\(_y\))\(^2\)(\(\pi\)2p\(_z\))\(^2\)(\(\pi^*\)2p\(_y\))\(^1\)
Removing electron from bonding \(\pi\)-orbital.
Step 3: Final Answer:
Electron lost from bonding \(\pi\)-orbital.
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