Question:
In the given circuit, the charge on \(4\ \mu\mathrm{F}\) capacitor will be : 
In the given circuit, the charge on \(4\ \mu\mathrm{F}\) capacitor will be :
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The 1 uF and 5 uF capacitors are in parallel (6 uF); this is in series with 4 uF, and that branch is across 10 V in parallel with the 3 uF capacitor.
Updated On: Nov 11, 2026
- \(5.4\ \mu\mathrm{C}\)
- \(9.6\ \mu\mathrm{C}\)
- \(13.4\ \mu\mathrm{C}\)
- \(24\ \mu\mathrm{C}\)
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The Correct Option is D
Solution and Explanation
1 \(\mu\)F and 5 \(\mu\)F are in parallel: \(C' = 1+5 = 6\ \mu\mathrm{F}\).
\(C'\) is in series with the 4 \(\mu\)F capacitor: \(C_{eq} = \frac{4\times 6}{4+6} = 2.4\ \mu\mathrm{F}\).
This branch is directly across the 10 V battery (the 3 \(\mu\)F capacitor is a separate parallel branch and does not affect it).
Charge on the series branch: \(Q = C_{eq}V = 2.4\times 10 = 24\ \mu\mathrm{C}\); series capacitors carry the same charge, so the 4 \(\mu\)F capacitor has 24 \(\mu\)C.
Answer: (4) \(24\ \mu\mathrm{C}\)
\(C'\) is in series with the 4 \(\mu\)F capacitor: \(C_{eq} = \frac{4\times 6}{4+6} = 2.4\ \mu\mathrm{F}\).
This branch is directly across the 10 V battery (the 3 \(\mu\)F capacitor is a separate parallel branch and does not affect it).
Charge on the series branch: \(Q = C_{eq}V = 2.4\times 10 = 24\ \mu\mathrm{C}\); series capacitors carry the same charge, so the 4 \(\mu\)F capacitor has 24 \(\mu\)C.
Answer: (4) \(24\ \mu\mathrm{C}\)
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