To solve this question, we need to analyze both the assertion and the reason provided, and determine if each statement is correct and if the reason is a valid explanation for the assertion.
The work done by an electric field when moving a charge on an equipotential surface is zero
because there is no change in electric potential energy. Electric lines of force are always
perpendicular to equipotential surfaces, meaning that any movement along the surface does
not alter the electric potential, confirming that no work is done.
The Correct answer is: Both (A) and (R) are correct and (R) is the correct explanation of (A)
Consider the following reaction of benzene. the percentage of oxygen is _______ %. (Nearest integer) 
Two p-n junction diodes \(D_1\) and \(D_2\) are connected as shown in the figure. \(A\) and \(B\) are input signals and \(C\) is the output. The given circuit will function as a _______. 