Question:
In the given circuit, if the forward biased resistance of each diode is \(20\,\Omega\) and the reverse biased resistance of each diode is infinity, then the value of current \(I\) is:
In the given circuit, if the forward biased resistance of each diode is \(20\,\Omega\) and the reverse biased resistance of each diode is infinity, then the value of current \(I\) is:
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While solving diode circuits, first replace every forward biased diode by its forward resistance and every reverse biased diode by an open circuit. Then use ordinary circuit analysis.
Updated On: Jun 12, 2026
- \(0.5\,\text{A}\)
- \(0.3\,\text{A}\)
- \(0.15\,\text{A}\)
- \(0.25\,\text{A}\)
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The Correct Option is A
Solution and Explanation
Concept:
For ideal diode circuit analysis, a forward biased diode behaves like a small resistance while a reverse biased diode behaves as an open circuit. Therefore, the first step is to identify the conducting path and then reduce the network into an equivalent resistance circuit.
Step 1: Identify the conducting diodes. From the polarity of the source and the orientation of the diodes shown in the circuit, only the forward biased diodes conduct current. The reverse biased diodes act as open circuits because their resistance is infinite. Thus the conducting branch contains: \[ 20\Omega +20\Omega \] and the external series resistance \[ 20\Omega \]
Step 2: Determine the equivalent resistance. The conducting path offers a total resistance \[ R_{\text{eq}} = 20+20+20 = 60\Omega \]
Step 3: Apply Ohm's law. Given source voltage \[ V=12\text{ V} \] Hence \[ I = \frac{V}{R} = \frac{12}{24} \] \[ I=0.5\text{ A} \] Therefore, \[ \boxed{I=0.5\text{ A}} \]
Step 1: Identify the conducting diodes. From the polarity of the source and the orientation of the diodes shown in the circuit, only the forward biased diodes conduct current. The reverse biased diodes act as open circuits because their resistance is infinite. Thus the conducting branch contains: \[ 20\Omega +20\Omega \] and the external series resistance \[ 20\Omega \]
Step 2: Determine the equivalent resistance. The conducting path offers a total resistance \[ R_{\text{eq}} = 20+20+20 = 60\Omega \]
Step 3: Apply Ohm's law. Given source voltage \[ V=12\text{ V} \] Hence \[ I = \frac{V}{R} = \frac{12}{24} \] \[ I=0.5\text{ A} \] Therefore, \[ \boxed{I=0.5\text{ A}} \]
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