Question:

In the following reaction sequence:
I. Formation of A has proceeded with racemisation.
II. Formation of B has proceeded with inversion.
Select the correct statement.

Show Hint

S\(_N\)1: racemisation; S\(_N\)2: inversion; S\(_N\)1 at chiral centre gives racemic mixture.
Updated On: Apr 23, 2026
  • I and II
  • Only I
  • Only III
  • None of these
Show Solution
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
S\(_N\)1 reactions give racemisation (via carbocation). S\(_N\)2 reactions give inversion of configuration.
Step 2: Detailed Explanation:
Formation of A via S\(_N\)1: carbocation intermediate, attack from either side \(\Rightarrow\) racemisation.
Formation of B via S\(_N\)2: backside attack \(\Rightarrow\) inversion.
Both statements I and II are correct.
Step 3: Final Answer:
Thus, both I and II are correct.
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