Question:
In the following figure, the current I is equal to
In the following figure, the current I is equal to
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Apply Kirchhoff's current law at each junction in turn.
Updated On: Oct 1, 2026
- \(2.9\) A
- \(3.9\) A
- \(6.2\) A
- \(7.5\) A
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
At any junction, the current entering equals the current leaving.
Step 2: Key Formula or Approach
Move from left to right through the three junctions of the figure.
Step 3: Detailed Explanation
Left junction: in \(4.5+1.7=6.2\) A, out \(2.3\) A. So \(6.2-2.3=3.9\) A goes along the connecting wire.
Middle junction: in \(3.9+3.2+4.9=12.0\) A, out \(2.6\) A. So \(12.0-2.6=9.4\) A goes to the right.
Right junction: \(9.4=1.9+I\).
\[ I=9.4-1.9=7.5\ \text{A} \]
Final Answer:
The current \(I\) is 7.5 A, option (D). \[ \boxed{7.5\ \text{A (D)}} \]
At any junction, the current entering equals the current leaving.
Step 2: Key Formula or Approach
Move from left to right through the three junctions of the figure.
Step 3: Detailed Explanation
Left junction: in \(4.5+1.7=6.2\) A, out \(2.3\) A. So \(6.2-2.3=3.9\) A goes along the connecting wire.
Middle junction: in \(3.9+3.2+4.9=12.0\) A, out \(2.6\) A. So \(12.0-2.6=9.4\) A goes to the right.
Right junction: \(9.4=1.9+I\).
\[ I=9.4-1.9=7.5\ \text{A} \]
Final Answer:
The current \(I\) is 7.5 A, option (D). \[ \boxed{7.5\ \text{A (D)}} \]
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