Question:
In the figure shown, $m₁=10~kg$, $m₂=6$ kg, $m₃=4~kg$. If $T₃=40~N,$ $T₂=?$}
In the figure shown, $m₁=10~kg$, $m₂=6$ kg, $m₃=4~kg$. If $T₃=40~N,$ $T₂=?$}
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In the figure shown, $m1=10~kg$, $m2=6$ kg, $m3=4~kg$. If $T3=40~N,$ $T2=?$} \includegraphics[width=0.5\linewidth]47phy.png \labelfig:placeholder
Updated On: Apr 15, 2026
- 13 N
- 32 N
- 25 N
- 35 N
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The Correct Option is B
Solution and Explanation
Step 1: Analysis
Total force $T_{3}$ accelerates all three masses: $T_{3} = (m_{1} + m_{2} + m_{3})a$.
Step 2: Calculation
$40 = (10 + 6 + 4)a \Rightarrow 40 = 20a \Rightarrow a = 2 \text{ m/s}^{2}$.
Step 3: Finding $T_{2$}}
$T_{2}$ pulls $m_{1}$ and $m_{2}$: $T_{2} = (m_{1} + m_{2})a = (10 + 6) \times 2 = 32 \text{ N}$.
Final Answer: (b)
Total force $T_{3}$ accelerates all three masses: $T_{3} = (m_{1} + m_{2} + m_{3})a$.
Step 2: Calculation
$40 = (10 + 6 + 4)a \Rightarrow 40 = 20a \Rightarrow a = 2 \text{ m/s}^{2}$.
Step 3: Finding $T_{2$}}
$T_{2}$ pulls $m_{1}$ and $m_{2}$: $T_{2} = (m_{1} + m_{2})a = (10 + 6) \times 2 = 32 \text{ N}$.
Final Answer: (b)
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