Question:
In the figure, potential difference between A and B is : 
In the figure, potential difference between A and B is :
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Check the diode bias: the battery's positive terminal is on the A side, so the diode is forward biased and acts as a short (ideal). Then the 10 kOhm resistors form a series-parallel network.
Updated On: Oct 31, 2026
- 10 V
- 5 V
- zero
- 15 V
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The Correct Option is A
Solution and Explanation
Step 1: The long (positive) plate of the 30 V battery is at the top, so current flows through the 10 k resistor to A, and the diode (arrow pointing away from A) is forward biased, so it is treated as ideal with zero drop.
Step 2: Between A and B, the middle 10 k resistor is in parallel with (diode + 10 k): \(R_{AB}=\dfrac{10\times10}{10+10}=5\ \mathrm{k\Omega}\).
Step 3: Total resistance \(=10+5=15\ \mathrm{k\Omega}\), so \(I=\dfrac{30}{15\ \mathrm{k\Omega}}=2\) mA.
Step 4: \(V_{AB}=I\,R_{AB}=2\ \mathrm{mA}\times5\ \mathrm{k\Omega}=10\) V.
Answer: (A) 10 V
Step 2: Between A and B, the middle 10 k resistor is in parallel with (diode + 10 k): \(R_{AB}=\dfrac{10\times10}{10+10}=5\ \mathrm{k\Omega}\).
Step 3: Total resistance \(=10+5=15\ \mathrm{k\Omega}\), so \(I=\dfrac{30}{15\ \mathrm{k\Omega}}=2\) mA.
Step 4: \(V_{AB}=I\,R_{AB}=2\ \mathrm{mA}\times5\ \mathrm{k\Omega}=10\) V.
Answer: (A) 10 V
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