Question

In the figure below, what is the potential difference between the point A and B and between B and C respectively in steady state? 

• A. \(V_{AB}=V_{BC}=100\,\text{V}\)
• B. \(V_{AB}=75\,\text{V},\; V_{BC}=25\,\text{V}\)
• C. \(V_{AB}=25\,\text{V},\; V_{BC}=75\,\text{V}\)
• D. VAB=VBC=50V

Hint:

In DC steady state: • Capacitors behave as open circuits • Only resistive networks decide potential differences

Answer 1

The Correct Option is D

Step 1: In steady state, capacitors act as open circuits and no current flows through them.
Step 2: Only the resistive path remains active. The resistors of 20Ω and 10Ω are in series with a 100V battery.
Step 3: Total resistance: Rₑq = 20 + 10 = 30Ω
Step 4: Current in the circuit: I = (100)/(30) = (10)/(3)A
Step 5: Potential drops: VAB = I × 20 = (10)/(3)×20 = 50V VBC = I × 10 = (10)/(3)×10 = 50V