Question:
If the potential of a capacitor of capacity 6 μF is increased from 10 V to 20 V, the increase in its energy will be:
If the potential of a capacitor of capacity 6 μF is increased from 10 V to 20 V, the increase in its energy will be:
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Capacitor energy depends on square of voltage.
Updated On: Mar 18, 2026
- 4 × 10⁻⁴ J
- 4 × 10⁻⁶ J
- 9 × 10⁻⁴ J
- 12 × 10⁻⁶ J
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The Correct Option is C
Solution and Explanation
Step 1: Energy formula of capacitor. U = (1)/(2)CV²
Step 2: Calculating energies. Initial energy: U₁ = (1)/(2) × 6×10⁻⁶ × 10² Final energy: U₂ = (1)/(2) × 6×10⁻⁶ × 20²
Step 3: Increase in energy. Δ U = U₂ - U₁ = 9 × 10⁻⁴ J
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