Question:
In the F$_2$ generation of a dihybrid cross of homozygous parents, the number of genotypes and phenotypes will be respectively ______________.
In the F$_2$ generation of a dihybrid cross of homozygous parents, the number of genotypes and phenotypes will be respectively ______________.
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Dihybrid cross follows Mendel’s law of independent assortment.
Updated On: Mar 6, 2026
- 16 and 9
- 4 and 9
- 9 and 4
- 9 and 16
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The Correct Option is A
Solution and Explanation
Step 1: Understanding dihybrid cross.
A dihybrid cross involves two pairs of contrasting traits, such as seed shape and seed colour in pea plants.
Step 2: F$_2$ generation outcome.
When heterozygous individuals are crossed, the F$_2$ generation produces a 9:3:3:1 phenotypic ratio.
Step 3: Counting genotypes and phenotypes.
Total number of possible genotypes in F$_2$ generation = 16.
Total number of phenotypic combinations = 9.
Step 4: Conclusion.
The correct number of genotypes and phenotypes are 16 and 9 respectively.
A dihybrid cross involves two pairs of contrasting traits, such as seed shape and seed colour in pea plants.
Step 2: F$_2$ generation outcome.
When heterozygous individuals are crossed, the F$_2$ generation produces a 9:3:3:1 phenotypic ratio.
Step 3: Counting genotypes and phenotypes.
Total number of possible genotypes in F$_2$ generation = 16.
Total number of phenotypic combinations = 9.
Step 4: Conclusion.
The correct number of genotypes and phenotypes are 16 and 9 respectively.
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