
Using the equation:
\[ i = K\theta, \]
At half deflection:
\[ \frac{2}{G + R} = K\theta. \]
Rearranging:
\[ \frac{1}{\theta} = \frac{(G + R)K}{2} = RK + \frac{GK}{2}. \]
From the slope of the graph:
\[ \text{Slope} = K = 0.5 = 5 \times 10^{-1} \, \text{A/division}. \]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
