Question:
In the circuit shown here, the voltage across E and C are respectively 300 V and 400 V. The voltage E of the ac source is :
In the circuit shown here, the voltage across E and C are respectively 300 V and 400 V. The voltage E of the ac source is :
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In a series LC circuit, the inductor and capacitor voltages are in opposite phase, so the source voltage is the magnitude of their difference.
Updated On: Oct 31, 2026
- 400 Volt
- 500 Volt
- 100 Volt
- 700 Volt
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The Correct Option is C
Solution and Explanation
The circuit is a series L-C circuit with an ac source (no resistance).
Current is common; \(V_L\) leads the current by \(90^\circ\) and \(V_C\) lags it by \(90^\circ\), so \(V_L\) and \(V_C\) are \(180^\circ\) out of phase.
The given voltages are 300 V and 400 V (taken as the voltages across L and C).
\(E = |V_C - V_L| = 400 - 300 = 100\ \mathrm{V}\).
Answer: (3) 100 Volt
Current is common; \(V_L\) leads the current by \(90^\circ\) and \(V_C\) lags it by \(90^\circ\), so \(V_L\) and \(V_C\) are \(180^\circ\) out of phase.
The given voltages are 300 V and 400 V (taken as the voltages across L and C).
\(E = |V_C - V_L| = 400 - 300 = 100\ \mathrm{V}\).
Answer: (3) 100 Volt
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