Question:
In the Boolean Algebra \(\overline{A \cdot B}\) is same as
In the Boolean Algebra \(\overline{A \cdot B}\) is same as
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De Morgan's laws are fundamental in digital electronics and Boolean algebra.
Updated On: Apr 23, 2026
- \(\overline{A} + \overline{B}\)
- \(A \cdot B\)
- \(\overline{A} - \overline{B}\)
- \(A + B\)
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
De Morgan's theorem: \(\overline{A \cdot B} = \overline{A} + \overline{B}\).
Step 2: Detailed Explanation:
De Morgan's first law: Complement of product equals sum of complements.
Also, \(\overline{A + B} = \overline{A} \cdot \overline{B}\).
Step 3: Final Answer:
Thus, \(\overline{A \cdot B} = \overline{A} + \overline{B}\).
De Morgan's theorem: \(\overline{A \cdot B} = \overline{A} + \overline{B}\).
Step 2: Detailed Explanation:
De Morgan's first law: Complement of product equals sum of complements.
Also, \(\overline{A + B} = \overline{A} \cdot \overline{B}\).
Step 3: Final Answer:
Thus, \(\overline{A \cdot B} = \overline{A} + \overline{B}\).
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