Question:
In the amplitude modulation mode of transmission, the normal speech signal is with a maximum frequency of 5 kHz. If the carrier frequency is 200 kHz, the modulated signal will have the frequencies varying between
In the amplitude modulation mode of transmission, the normal speech signal is with a maximum frequency of 5 kHz. If the carrier frequency is 200 kHz, the modulated signal will have the frequencies varying between
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Bandwidth = \(2f_m\).
Updated On: May 1, 2026
- 190–210
- 195–205
- 195–200
- 200–205
- 199.5–200.5
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The Correct Option is B
Solution and Explanation
Concept: Frequency range in modulation
In amplitude modulation, the transmitted signal contains: - Carrier frequency $f_c$ - Upper sideband $f_c + f_m$ - Lower sideband $f_c - f_m$
Step 1: Given values
\[ f_c = 200,\quad f_m = 5 \]
Step 2: Calculate side frequencies
Lower sideband: \[ f_c - f_m = 200 - 5 = 195 \] Upper sideband: \[ f_c + f_m = 200 + 5 = 205 \]
Step 3: Frequency range
\[ 195 \text{ to } 205 \] Final Answer:
\[ \boxed{195\text{–}205} \] Note:
Bandwidth of AM signal $= 2f_m = 10$.
In amplitude modulation, the transmitted signal contains: - Carrier frequency $f_c$ - Upper sideband $f_c + f_m$ - Lower sideband $f_c - f_m$
Step 1: Given values
\[ f_c = 200,\quad f_m = 5 \]
Step 2: Calculate side frequencies
Lower sideband: \[ f_c - f_m = 200 - 5 = 195 \] Upper sideband: \[ f_c + f_m = 200 + 5 = 205 \]
Step 3: Frequency range
\[ 195 \text{ to } 205 \] Final Answer:
\[ \boxed{195\text{–}205} \] Note:
Bandwidth of AM signal $= 2f_m = 10$.
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