In photoelectric effect experiment, if the frequency of incident radiation (\(v\)) is increased, keeping all other factors constant, the stopping potential, ( \(v > v_0\)) (\(v_0\) = threshold frequency)
Show Hint
- decreases
- remains the same
- increases
- becomes zero
The Correct Option is C
Solution and Explanation
The stopping potential satisfies \(eV_0 = h\nu - h\nu_0\).
Step 2: Detailed Explanation
As \(\nu\) increases (with \(\nu > \nu_0\)), the maximum kinetic energy of the emitted electrons increases, so a larger stopping potential is needed. \(V_0\) is a linear function of frequency with positive slope \(h/e\).
It does not stay the same (B) and it does not decrease (A). It would be zero only at the threshold frequency.
Final Answer:
The stopping potential increases, option (C). \[ \boxed{\text{Increases}} \]
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