The photoelectric effect is described by Einstein's photoelectric equation: \[ h\nu = \phi + \text{KE}_{\text{max}}, \] where:
\( h \nu \) is the energy of the incident photon,
\( \phi \) is the work function (minimum energy required to emit an electron),
\( \text{KE}_{\text{max}} \) is the maximum kinetic energy of the emitted photoelectrons.
Analysis of statements:
\( A: \) True. The photocurrent (number of photoelectrons emitted per second) is proportional to the intensity of the incident radiation, which determines the number of photons.
\( B: \) False. The maximum kinetic energy of photoelectrons depends on the frequency, not the intensity.
\( C: \) True. The maximum kinetic energy depends on the frequency of the incident light (\( \nu \)) through the equation \( \text{KE}_{\text{max}} = h\nu - \phi \).
\( D: \) False. The emission of photoelectrons depends on the frequency of the light exceeding the threshold frequency, not intensity.
\( E: \) False. The maximum kinetic energy depends on the frequency.
Final Answer: The correct statements are: \[ \boxed{\text{(3) \( A \) and \( C \) only}}. \]
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)