Question:

In lactic acid fermentation, NADH is oxidized back to $\text{NAD}^+$ by ______.

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The primary physiological goal of fermentation is not actually to produce lactic acid or ethanol, but to regenerate the cellular supply of $\text{NAD}^+$ so that glycolysis can continue generating ATP in the absence of oxygen.
Updated On: Jun 30, 2026
  • Pyruvate
  • Lactate
  • Glucose
  • Acetyl Co-A
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
The question asks to identify the molecular species that acts as the electron acceptor to oxidize NADH back to $\text{NAD}^+$ during homolactic or heterolactic acid fermentation.
This biochemical step is essential for maintaining glycolysis in anaerobic conditions.

Step 2: Detailed Explanation:


Glycolysis and NAD+ Depletion: During the pathway of glycolysis, glucose is broken down into two molecules of pyruvate. In this process, $\text{NAD}^+$ is reduced to NADH by the enzyme glyceraldehyde-3-phosphate dehydrogenase.

The Regeneration Bottleneck: Because cells contain a limited pool of coenzyme $\text{NAD}^+$, glycolysis would quickly halt if NADH were not oxidized back to $\text{NAD}^+$. Under anaerobic conditions, oxidative phosphorylation in the mitochondria cannot occur to regenerate $\text{NAD}^+$.

Lactic Acid Fermentation Pathway: To solve this bottleneck, lactic acid bacteria (such as Lactobacillus and Lactococcus) utilize the enzyme lactate dehydrogenase (LDH).

Role of Pyruvate: The enzyme LDH transfers electrons directly from NADH to pyruvate (the end product of glycolysis). In this reaction:

• Pyruvate is reduced to lactate (lactic acid).

• NADH is oxidized back to $\text{NAD}^+$.

Other Options: Lactate is the reduced product, not the oxidizing agent. Glucose is the starting material of glycolysis. Acetyl Co-A is a metabolic intermediate of aerobic respiration, not involved in anaerobic lactic acid fermentation.

Step 3: Final Answer:

During lactic acid fermentation, pyruvate acts as the terminal electron acceptor that oxidizes NADH back to $\text{NAD}^+$, corresponding to option (A).
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