Question:

In case of well of death which is a vertical cylindrical wall of radius ' \(r\) ' inside which vehicle is driven in horizontal circles. If ' \(m\) ' is mass of vehicle, ' \(V\) ' is the velocity and ' \(\mu_s\) ' is the coefficient of static friction between the wheels of vehicle and walls then correct relation is [ \(g\) = acceleration due to gravity]

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Well of death: Friction supports weight
Updated On: May 8, 2026
  • \(V^2 \le \frac{rg}{\mu_s}\)
  • \(V \le \frac{rg}{\mu_s}\)
  • \(V^2 \ge \frac{rg}{\mu_s}\)
  • \(V \ge \frac{rg}{\mu_s}\)
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The Correct Option is C

Solution and Explanation


Concept: For circular motion: \[ \text{Normal force} = \frac{mv^2}{r} \] Friction balances weight: \[ \mu_s N \ge mg \]

Step 1:
Substitute $N$. \[ \mu_s \cdot \frac{mv^2}{r} \ge mg \]

Step 2:
Simplify. \[ v^2 \ge \frac{rg}{\mu_s} \]

Step 3:
Conclusion.
Required condition: \[ V^2 \ge \frac{rg}{\mu_s} \] Final Answer: Option (C)
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