Question:

In \(\beta\)-decay, when a proton converts into a neutron, the particles emitted are

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Remember, \[ \boxed{ p\rightarrow n+e^++\nu_e } \] (\(\beta^+\)-decay) and \[ \boxed{ n\rightarrow p+e^-+\bar{\nu}_e } \] (\(\beta^-\)-decay).
Updated On: Jul 18, 2026
  • Electron, neutrino
  • Positron, neutrino
  • Positron, antineutrino
  • Electron, antineutrino
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The Correct Option is B

Solution and Explanation

Step 1: Write the nuclear reaction for \(\beta^+\)-decay. When a proton converts into a neutron, the reaction is \[ p \rightarrow n+e^++\nu_e, \] where \[ e^+ \] is a positron and \[ \nu_e \] is an electron neutrino.

Step 2:
Identify the emitted particles. Thus, the emitted particles are \[ \boxed{\text{Positron and neutrino}.} \] Hence, the correct option is \(\boxed{(B)}\).
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