Question:

In amplitude modulation, if the amplitude of the message signal is increased by \(20\%\) and the amplitude of the carrier wave is decreased by \(20\%\), then the percentage increase in the modulation index is

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The modulation index in AM is \[ \boxed{ m=\frac{A_m}{A_c}. } \] Any percentage change in \(A_m\) or \(A_c\) directly changes the modulation index according to this ratio.
Updated On: Jul 18, 2026
  • \(75\)
  • \(40\)
  • \(25\)
  • \(50\)
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The Correct Option is D

Solution and Explanation

Step 1: Recall the expression for modulation index. For amplitude modulation, \[ m=\frac{A_m}{A_c}, \] where \[ A_m \] is the amplitude of the message signal and \[ A_c \] is the amplitude of the carrier wave.

Step 2:
Find the new modulation index. The message amplitude is increased by \(20\%\), so \[ A_m'=1.2A_m. \] The carrier amplitude is decreased by \(20\%\), so \[ A_c'=0.8A_c. \] Hence, \[ m' = \frac{A_m'}{A_c'} = \frac{1.2A_m}{0.8A_c} = 1.5m. \]

Step 3:
Calculate the percentage increase. The increase in modulation index is \[ 1.5m-m=0.5m. \] Therefore, \[ \text{Percentage increase} = \frac{0.5m}{m}\times100 = 50\%. \] Hence, \[ \boxed{50\%.} \] Therefore, the correct option is \(\boxed{(D)}\).
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