In a zero-order reaction,the reactant A disappeared with a rate of reaction k=0.04 Msec-1. The initial concentration of A is 1 M. What will be the concentration of A after 20 seconds?
1.08 M
0.2 M
0.8 M
0.002 M
0.008 M
Given parameters:
Zero-order rate equation: \[ [A]_t = [A]_0 - kt \] \[ [A]_t = 1 - (0.04 \times 20) \] \[ [A]_t = 1 - 0.8 = 0.2 \, \text{M} \]
Thus, the correct option is (B): 0.2 M.
1. Zero-order reaction rate law:
For a zero-order reaction, the rate of reaction is independent of the concentration of the reactant. The integrated rate law for a zero-order reaction is:
\[[A]_t = [A]_0 - kt\]
where:
2. Substitute the given values:
\([A]_0 = 1 \, M\)
\(k = 0.04 \, M \, sec^{-1}\)
\(t = 20 \, sec\)
\[[A]_t = 1 - (0.04)(20)\]
3. Perform the calculation:
\[[A]_t = 1 - 0.8 = 0.2 \, M\]
4. Final answer:
The concentration of A after 20 seconds is 0.2 M.
Thus, the correct option is (B) 0.2 M.
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
The rate of a chemical reaction is defined as the change in concentration of any one of the reactants or products per unit time.
Consider the reaction A → B,
Rate of the reaction is given by,
Rate = −d[A]/ dt=+d[B]/ dt
Where, [A] → concentration of reactant A
[B] → concentration of product B
(-) A negative sign indicates a decrease in the concentration of A with time.
(+) A positive sign indicates an increase in the concentration of B with time.
There are certain factors that determine the rate of a reaction: