Question:

In a Zener diode regulated power supply, unregulated d.c. input of $10$ V is applied. If the resistance $R_s$ connected in series with a Zener diode is $200\,\Omega$ and the Zener voltage $V_z = 5$ V, the current across the resistance $R_s$ is

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Zener circuit: current = $\frac{V_{in} - V_z}{R}$.
Updated On: May 2, 2026
  • $15$ mA
  • $10$ mA
  • $20$ mA
  • $5$ mA
  • $25$ mA
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Solution and Explanation

Concept: Zener diode voltage regulation
In breakdown region: \[ V_z = \text{constant} \] Voltage across resistor: \[ V_R = V_{in} - V_z \] ---

Step 1: Calculate voltage across resistor
\[ V_R = 10 - 5 = 5 \text{ V} \] ---

Step 2: Apply Ohm's law
\[ I = \frac{V_R}{R} \] \[ I = \frac{5}{200} = 0.025 \text{ A} \] ---

Step 3: Convert to mA
\[ I = 25 \text{ mA} \] --- Physical Insight:
• Zener maintains constant voltage
• Excess voltage drops across resistor --- Final Answer: \[ \boxed{25 \text{ mA}} \]
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