In a ‘tug of war’ game, two persons pull each other through a massless rope. The person who wins is
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- One whose weight is less
- One who exerts more friction force (shearing force) on the ground
- One who exerts more normal force (compressing force) on the ground
- One who pulls the rope with a greater force
One whose weight is more
The Correct Option is B
Solution and Explanation
Step 1: In a tug-of-war, the force exerted on the rope does not directly determine the winner. Instead, it depends on the force that a person can apply against the ground.
Step 2: The force that allows a person to pull effectively comes from the friction between their feet and the ground. Higher friction provides better resistance, allowing one to pull with greater force.
Step 3: The friction force is given by: \[ F_{{friction}} = \mu N \] where $\mu$ is the coefficient of friction and $N$ is the normal force.
Step 4: The person who can exert a larger frictional force will be able to resist the pull of the opponent and apply a stronger opposing force, ultimately winning the game.
Step 5: Therefore, the correct answer is (B). \bigskip
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