Question:

In a triangle \(ABC\), if \[ a=4,\quad b=5,\quad c=7, \] then \[ \sin\left(\frac{A}{2}\right) \] is

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Remember the standard half-angle formula in a triangle: \[ \sin\left(\frac{A}{2}\right) = \sqrt{\frac{(s-b)(s-c)}{bc}}, \] where \(s=\frac{a+b+c}{2}\) is the semi-perimeter.
Updated On: Jun 26, 2026
  • \(\sqrt{\frac{3}{35}}\)
  • \(\sqrt{\frac{35}{3}}\)
  • \(\sqrt{\frac{2}{35}}\)
  • \(\sqrt{\frac{1}{35}}\)
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The Correct Option is A

Solution and Explanation

Step 1: Find the semi-perimeter.
For a triangle, \[ s=\frac{a+b+c}{2} \] Substituting the given values, \[ s=\frac{4+5+7}{2} \] \[ s=\frac{16}{2}=8 \]

Step 2: Use the half-angle formula.
The formula for the half-angle of a triangle is \[ \sin\left(\frac{A}{2}\right) = \sqrt{\frac{(s-b)(s-c)}{bc}} \] Substituting \[ s=8,\quad b=5,\quad c=7, \] we get \[ \sin\left(\frac{A}{2}\right) = \sqrt{\frac{(8-5)(8-7)}{5\cdot 7}} \] \[ = \sqrt{\frac{3\cdot 1}{35}} \] \[ = \sqrt{\frac{3}{35}} \]

Step 3: Verify the result.
Since \(A\) is an angle of a triangle, \[ 0\lt A\lt \pi \] Therefore, \[ \sin\left(\frac{A}{2}\right)\gt 0, \] and the positive square root is taken.

Step 4: Final conclusion.
Hence, \[ \boxed{\sin\left(\frac{A}{2}\right)=\sqrt{\frac{3}{35}}} \] Therefore, the correct option is \[ \boxed{(1)} \]
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