In a step-up transformer the voltage in the primary is $220\mathrm{V}$ and the current is $5\mathrm{A}$. The secondary voltage is found to be $22000\mathrm{V}$. The current in the secondary (neglect losses) is
Show Hint
- $5\mathrm{A}$
- $50\mathrm{A}$
- $500\mathrm{A}$
- $0.05\mathrm{A}$
The Correct Option is D
Solution and Explanation
For an ideal transformer, $V_p I_p = V_s I_s$.
Step 2: Detailed Explanation:
$I_s = \frac{V_p I_p}{V_s} = \frac{220 \times 5}{22000} = \frac{1100}{22000} = 0.05$ A.
Step 3: Final Answer:
The current in the secondary is $0.05$ A.
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