In a Millikan’s oil drop experiment, the charge on an oil drop is calculated to be \( 6.35 \times 10^{-19} \, \text{C} \). The number of excess electrons on the drop is:
Show Hint
The number of excess electrons on an oil drop is calculated by dividing the total charge by the charge of a single electron.
Step 1: Formula for number of excess electrons.
The number of excess electrons is given by:
\[
n = \frac{q}{e}
\]
where \( q \) is the total charge and \( e \) is the charge of an electron.
Step 2: Calculation.
Substituting the given charge of the drop and the charge of an electron:
\[
n = \frac{6.35 \times 10^{-19}}{1.6 \times 10^{-19}} = 6
\]
Final Answer:
\[
\boxed{6}
\]