Concept:
In rectifier filter circuits, capacitor smooths pulsating DC output.
Ripple decreases when capacitor discharges slowly through load resistance.
Time constant:
$$\tau = RC$$
Step 1: Effect of large capacitance.
If $C$ is large, then
$$\tau = RC$$
also becomes large.
Large time constant means capacitor loses charge slowly between peaks.
Step 2: Why useful in rectifier.
Slow discharge keeps output voltage more constant and reduces ripple.
Hence capacitor acts as better filter.
Step 3: Check options.
(A) Ripple decreases, not increases.
(B) Peak voltage is not reduced mainly for this reason.
(C) Correct.
(D) Large capacitor discharges slowly, not quickly.
(E) False.
Hence correct option is (C). :contentReference[oaicite:1]{index=1}