Question:

In a cross (AaBbCCDdEE) × (AABbCcDdEe), what is the probability that any particular gamete from the female parent will be AbCdE?

Show Hint

Gamete probability:
- Heterozygous (Aa): 1/2 for each allele.
- Homozygous (AA): 1 for the allele.
- Multiply probabilities for each gene.
  • 1/4
  • 1/6
  • 1/16
  • 1/8
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Question:
This question tests knowledge of probability in genetics, specifically gamete formation.

Step 2: Key Formula or Approach:

The probability of a particular gamete is the product of the probabilities of each allele.
For each heterozygous gene, the probability of passing a specific allele is 1/2.
For homozygous genes, the probability is 1.

Step 3: Detailed Explanation:

Female parent genotype: AaBbCCDdEE
We need the probability of gamete AbCdE:
- A: From Aa, probability of A = 1/2.
- b: From Bb, probability of b = 1/2.
- C: From CC, probability of C = 1 (homozygous).
- d: From Dd, probability of d = 1/2.
- E: From EE, probability of E = 1 (homozygous).
Total probability = \(1/2 \times 1/2 \times 1 \times 1/2 \times 1 = 1/8\).
Thus, the probability is 1/8.

Step 4: Final Answer:

Thus, the probability that a gamete will be AbCdE is 1/8, which corresponds to option (D).
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