Question:
In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be:
In a common emitter amplifier circuit using an n-p-n transistor, the phase difference between the input and the output voltages will be:
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A common emitter amplifier is a phase-inverting amplifier.
Updated On: Nov 11, 2026
- \(180^\circ\)
- \(45^\circ\)
- \(90^\circ\)
- \(135^\circ\)
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The Correct Option is A
Solution and Explanation
In a CE amplifier the input signal is applied to the base-emitter junction and the output is taken from the collector.
When the input voltage rises, the base current and hence the collector current \(I_C\) increase.
The output voltage is \(V_{CE} = V_{CC} - I_C R_L\), so a larger \(I_C\) gives a smaller output voltage.
Thus the output decreases when the input increases and vice versa: the output is inverted with respect to the input.
Phase difference = \(180^\circ\).
Answer: (1) \(180^\circ\)
When the input voltage rises, the base current and hence the collector current \(I_C\) increase.
The output voltage is \(V_{CE} = V_{CC} - I_C R_L\), so a larger \(I_C\) gives a smaller output voltage.
Thus the output decreases when the input increases and vice versa: the output is inverted with respect to the input.
Phase difference = \(180^\circ\).
Answer: (1) \(180^\circ\)
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