Question:

If y=2x3−2x2+3x−5, then for x=2 and Δx=0.1 value of Δy is:

Updated On: Feb 15, 2024
  • (A) 2.002
  • (B) 1.9
  • (C) 0
  • (D) 0.9
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The Correct Option is B

Solution and Explanation

Explanation:
Given:y=2x3−2x2+3x−5⇒dydx=6x2−4x+3⇒(dydx)x=2=24−8+3=19∵Δy=(dydx)x=2Δx⇒Δy=19×(0.1)=1.9Hence, the correct option is (B).
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