Question:

If x,y,z are complex numbers, and Δ= beginvmatrix 0 & -y & -z
bary & 0 & -x
barz & barx & 0 endvmatrix, then Δ is:

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Determinants with conjugate symmetry often yield purely real or imaginary values.
Updated On: Mar 20, 2026
  • purely real
  • purely imaginary
  • complex
  • 0
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The Correct Option is B

Solution and Explanation


Step 1:
Observe that the determinant involves complex conjugate pairs.
Step 2:
On expansion, Δ becomes the negative of its own conjugate.
Step 3:
Hence Δ+Δ=0, implying Δ is purely imaginary.
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